3(4x)^2=49200

Solution for 3(4x)^2=49200 equation:

3(4x)^2=49200

We move all terms to the left:

3(4x)^2-(49200)=0

a = 34; b = 0; c = -49200;
Δ = b2-4ac
Δ = 02-4·34·(-49200)
Δ = 6691200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6691200}=\sqrt{1600*4182}=\sqrt{1600}*\sqrt{4182}=40\sqrt{4182}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{4182}}{2*34}=\frac{0-40\sqrt{4182}}{68}
=-\frac{40\sqrt{4182}}{68}
=-\frac{10\sqrt{4182}}{17}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{4182}}{2*34}=\frac{0+40\sqrt{4182}}{68}
=\frac{40\sqrt{4182}}{68}
=\frac{10\sqrt{4182}}{17}
$